let $\displaystyle f(x)=(x-1)(x-2)(x-3)(x-4)(x-5)$. This function has five roots on the interval $\displaystyle [0,7]$. I have to use the bisection method on this interval and figure out what root is located.

I'm not entirely sure I know how to use this method correctly..

Here it goes,

First, since $\displaystyle f(0)<0$ and $\displaystyle f(7)>0$, there exists a $\displaystyle c\in\mathbb{R}$ in between those two points such that $\displaystyle f(c) = 0$ ..

Now would you divide the interval in two?