http://i45.tinypic.com/mtbkvs.jpg

I can kind of see whats going on, but not well enough to construct a logical progression towards a proof. Any ideas?

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- Mar 2nd 2010, 07:50 PMdavismjEntire bounded function must be constant.
http://i45.tinypic.com/mtbkvs.jpg

I can kind of see whats going on, but not well enough to construct a logical progression towards a proof. Any ideas? - Mar 2nd 2010, 08:16 PMdavismjThis feels like the solution.
http://i45.tinypic.com/2iu6h5f.jpg

This feels right, but I tend to get things wrong with my ignorance. Verify? - Mar 3rd 2010, 07:07 AMOpalg
That basic idea (taking the exponential) is exactly what is needed, but some of the details are a bit dubious. You can use inequalities for real numbers, but not for complex numbers. It would be better to say and therefore (since and ). Then apply Liouville's theorem.

- Mar 3rd 2010, 09:17 AMdavismj