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About LinkBacksOriginally Posted by summerset353
First ,, second the polynomial you wrote has no real roots at all since all the powers of x are even and thus its minimal value is
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Tonio
Prove the polynomial x^6 + x^4 +5x^2 + 1 has at least four real roots.
This is what I have so far:
1. f(x)=x^6 + x^4 +5x^2 + 1 is continuous because it is a polynomial
2. f(0)= 1>0
3. f(-1)= -2<0
Since 1-3 are satisfied, there exists x in (0,1) such that for f(x)=0
Using f(-0.5), f(-0.75), f(-0.875) we can find a root.
My question is: Is there another way of find the roots besides the way I'm doing it since I not only have to find one root, i have to find four?
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