Prove that F'(z) = f(z) by Power Series expansion.
Please focus on 19-b) at the bottom. I'm not sure how hard this is supposed to be, or where $\displaystyle |z-z_0| < R$ comes in. I think I must be missing something.
Please focus on 19-b) at the bottom. I'm not sure how hard this is supposed to be, or where $\displaystyle |z-z_0| < R$ comes in. I think I must be missing something.
Thanks!
You need the fact that $\displaystyle |z-z_0|< R$ to ensure that your move of the derivative from outside the sum to inside was kosher.
Last edited by Jhevon; Feb 21st 2010 at 10:33 PM.
Reason: fixed LaTeX