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Math Help - Simple Power Series Question

  1. #1
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    Smile Simple Power Series Question



    Is this sufficient for the question asked? or does that extra -1 make it less of a power series?

    Thanks!
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  2. #2
    MHF Contributor Drexel28's Avatar
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    Quote Originally Posted by davismj View Post


    Is this sufficient for the question asked? or does that extra -1 make it less of a power series?

    Thanks!
    I think you're missing a negative sign. \frac{1+z}{1-z}=-\left(1+\frac{2}{1+z}\right)...actually...two.
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    Quote Originally Posted by Drexel28 View Post
    I think you're missing a negative sign. \frac{1+z}{1-z}=-\left(1+\frac{2}{1+z}\right)...actually...two.
    I'm sorry, but that doesn't really help (except I see my typo!)

    From what I can tell, you've rewritten the original expression as

    \frac{1}{1-z} + \frac{z}{1-z} and of course \frac{1}{1-z} is \sum_{n=0}^{\infty}z^n

    Not sure where you're getting the negative sign from, though.
    Last edited by davismj; February 20th 2010 at 04:51 PM.
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