Let $\displaystyle p(z)=z^6+9z^4+z^3+2z+4$.

Determine which quadrants contain the two zeros of

$\displaystyle p(z)$ that lie outside the unit circle.

We have learned the argument principle in this section. However, I

don't see how to find the quadrants that the zeroes lie in. I wanted

to use De Moivre's formula; however, I don't think this problem is

just that easy.