Hello everyone Show: The operator T has no eigenvalues , where Proof: Iff it follows that and if I don't get it: how do we know that ? Help would be much appreciated Thanks Rapha
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Hi I think it should say . You agree? It is implicit in the definition of that
Originally Posted by Rapha Hello everyone Show: The operator T has no eigenvalues , where Proof: Iff it follows that and if I don't get it: how do we know that ? Look at the definition of T- the sum is . The crucial point is that there is NO " " in that. In order for that to be a multiple of x, there must be NO " " in x. That means that the coefficient of , , must be 0. Help would be much appreciated Thanks Rapha
Hi! Thank you so much! It would never have occurred to me. Your explanations made this excercise so easy. Rapha
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