http://i50.tinypic.com/2dhgx0x.jpg

Here's what I got (since $\displaystyle \frac{1}{2 - z} = \frac{-1}{z-2}$).

The book says the answer is $\displaystyle 2\pi i$, not $\displaystyle -2\pi i$. Who is right?

Printable View

- Feb 16th 2010, 01:40 PMdavismj[SOLVED] Application of Cauchy's Integral Formula
http://i50.tinypic.com/2dhgx0x.jpg

Here's what I got (since $\displaystyle \frac{1}{2 - z} = \frac{-1}{z-2}$).

The book says the answer is $\displaystyle 2\pi i$, not $\displaystyle -2\pi i$. Who is right? - Feb 16th 2010, 03:55 PMmabruka
The book is right. Check you have got the right singularity.

With "right" i mean the one who is inside your curve and apply the theorem as you just did. - Feb 16th 2010, 04:13 PMdavismj
- Feb 16th 2010, 05:33 PMmabruka
(Rofl)