Please help!! Need counter-example I believe
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Originally Posted by Phyxius117 Please help!! Need counter-example I believe a) What about
Originally Posted by Phyxius117 Please help!! Need counter-example I believe d.) Assuming this sequence is in the metric space , if converges, then it is bounded. ( such that ) So . (Triangle Inequality) But since is unbounded, so is , because is a fixed point. Therefore is unbounded as well. @ Drexel: needs to converge.
Originally Posted by Drexel28 a) What about Originally Posted by redsoxfan325 d.) Assuming this sequence is in the metric space , if converges, then it is bounded. ( such that ) So . (Triangle Inequality) But since is unbounded, so is , because is a fixed point. Therefore is unbounded as well. @ Drexel: needs to converge. a) is redonkulous then. Let and . Since they both converge we see that
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