Problem is find the inverse of $\displaystyle f(x) = x^2-2x+4$
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Originally Posted by Henryt999 Problem is find the inverse of $\displaystyle f(x) = x^2-2x+4$ The short answer is: you can't. There must be some restrictions. What are they?
Originally Posted by Plato The short answer is: you can't. There must be some restrictions. What are they? Ops, sorry it said: $\displaystyle f:[1,\infty)\rightarrow R, f(x) = x^2 -2x +4$
Set $\displaystyle x = y^2 - 2y + 4$ and solve for y.
Originally Posted by icemanfan Set $\displaystyle x = y^2 - 2y + 4$ and solve for y. Yes, thanks, that I understand I get $\displaystyle x-4 = y(y-2)$ And now what?
Originally Posted by Henryt999 Yes, thanks, that I understand I get $\displaystyle x-4 = y(y-2)$ And now what? Try this: $\displaystyle x = y^2 - 2y + 4$ $\displaystyle x = y^2 - 2y + 1 + 3$ $\displaystyle x = (y - 1)^2 + 3$ etc.
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