# Prove these integrals are equal

• Feb 7th 2010, 01:16 PM
paupsers
Prove these integrals are equal
Prove that

$\int_{0}^\infty x^2 e^{{-x}^{2}}=\frac{1}{2} \int_{0}^\infty e^{{-x}^{2}}$

and both integrals converge.

Any help on this? I tried doing integration by parts for the second one but couldn't reach an answer.
• Feb 7th 2010, 01:38 PM
Jhevon
Quote:

Originally Posted by paupsers
Prove that

$\int_{0}^\infty x^2 e^{{-x}^{2}}=\frac{1}{2} \int_{0}^\infty e^{{-x}^{2}}$

and both integrals converge.

Any help on this? I tried doing integration by parts for the second one but couldn't reach an answer.

see post #2 here
• Feb 7th 2010, 02:23 PM
paupsers

But now I'm trying to solve

$\int_0^\infty x^2e^{-x^2}dx$ by using the same method, and it's not working out so nicely. I've set it up the same way and converted it into polar, and now I'm at

$\int_0^\infty\int_0^{2\pi}r^5cos^2\theta sin^2\theta e^{-r^2}d\theta dr$ and I have a feeling that's not simple to evaluate... :-(

Is there a simpler way to do this?
• Feb 7th 2010, 02:37 PM
paupsers
Actually, it can be done using integration by parts. Thanks for the link, still!