Results 1 to 3 of 3

Thread: finding the principal argument

  1. January 30th 2010, 12:56 PM #1
    LCopper2010
    LCopper2010 is offline
    Newbie
    Joined
    Jan 2010
    Posts
    15

    finding the principal argument

    Find the principal argument of ( \sqrt{3}-i)^6.
    Last edited by Plato; January 30th 2010 at 03:15 PM. Reason: Fix LaTeX
    Follow Math Help Forum on Facebook and Google+
  2. January 30th 2010, 01:43 PM #2
    girdav
    girdav is offline
    Super Member girdav's Avatar
    Joined
    Jul 2009
    From
    Rouen, France
    Posts
    674
    Thanks
    32
    Use \arg\left(z\cdot z'\right)=\arg z +\arg z' \left[2\pi\right].
    Follow Math Help Forum on Facebook and Google+
  3. January 30th 2010, 03:12 PM #3
    Plato
    Plato is offline
    MHF Contributor
    Joined
    Aug 2006
    Posts
    16,995
    Thanks
    775
    Awards
    1
    MHF Donor
    Quote Originally Posted by LCopper2010 View Post
    Find the principal argument of ( \sqrt{3}-i)^6
    ( \sqrt{3}-i)=2\exp\left(\frac{-\pi}{6}\right) so ( \text{Arg}(\sqrt{3}-i)^6)=\pi
    Follow Math Help Forum on Facebook and Google+
« inequality proof | Riemann integral and null sets »

Similar Math Help Forum Discussions

  1. Complex Numbers (Principal Argument)
    Posted in the Algebra Forum
    Replies: 4
    Last Post: November 18th 2010, 02:41 AM
  2. which interval is commonly accepted for principal argument of complex numbers?
    Posted in the Differential Geometry Forum
    Replies: 2
    Last Post: December 18th 2009, 07:56 PM
  3. Complex Principal Argument #2
    Posted in the Calculus Forum
    Replies: 1
    Last Post: October 13th 2009, 09:18 PM
  4. Complex Principal Argument
    Posted in the Calculus Forum
    Replies: 1
    Last Post: October 13th 2009, 09:05 PM
  5. Principal Argument of the Complex Number -1 + i sqrt(3)
    Posted in the Pre-Calculus Forum
    Replies: 9
    Last Post: October 12th 2009, 03:04 AM

Search Tags


/mathhelpforum @mathhelpforum