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Math Help - finding the principal argument

  1. #1
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    finding the principal argument

    Find the principal argument of ( \sqrt{3}-i)^6.
    Last edited by Plato; January 30th 2010 at 03:15 PM. Reason: Fix LaTeX
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    Use \arg\left(z\cdot z'\right)=\arg z +\arg z' \left[2\pi\right].
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    Quote Originally Posted by LCopper2010 View Post
    Find the principal argument of ( \sqrt{3}-i)^6
    ( \sqrt{3}-i)=2\exp\left(\frac{-\pi}{6}\right) so ( \text{Arg}(\sqrt{3}-i)^6)=\pi
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