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Math Help - complex equation

  1. #1
    Newbie
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    complex equation

    I wonder if some one can help me with:

    1. to solve the equation

    2. to make the function with the e below to loran column

    I know it seems simple but for me it is a big help
    thank's alot
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  2. #2
    MHF Contributor

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    Quote Originally Posted by avazim View Post
    I wonder if some one can help me with:

    1. to solve the equation

    2. to make the function with the e below to loran column

    I know it seems simple but for me it is a big help
    thank's alot
    Solving the equation is pretty trivial isn't it? If cos^2(z)= -2 then either cos(z)= i\sqrt{2} or cos(z)= -i\sqrt{2}. If your calculator does not allow for inverse trig functions of imaginary numbers (my TI 89 does), use cos(z)= \frac{e^z+ e^{-z}}{2}= \pm i\sqrt{2}. Letting u= e^z makes the equation u^2+ 1= \pm 2 i\sqrt{2} u that you can solve with the quadratic equation.

    For (2), I simply don't know what you mean by " function with the e below to loran column".
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