# Thread: bounded domain, meromorphic functions

1. ## bounded domain, meromorphic functions

Let $D$ be a bounded domain, and let $f(z)$ and $h(z)$ be meromorphic functions on $D$ that extend to be analytic on $\partial D$. Suppose that $|h(z)|< |f(z)|$ on $\partial D$. Show by example that $f(z)$ and $f(z)+h(z)$ can have different numbers of zeros on $D$. What can be said about $f(z)$ and $f(z)+h(z)$? Prove your assertion.

I do not see what example I can use here. I think what we can say is that they have the same number of zeros minus poles. I just don't see an example here. Thanks.

2. Originally Posted by hilbertcube182
Let $D$ be a bounded domain, and let $f(z)$ and $h(z)$ be meromorphic functions on $D$ that extend to be analytic on $\partial D$. Suppose that $|h(z)|< |f(z)|$ on $\partial D$. Show by example that $f(z)$ and $f(z)+h(z)$ can have different numbers of zeros on $D$. What can be said about $f(z)$ and $f(z)+h(z)$? Prove your assertion.

I do not see what example I can use here. I think what we can say is that they have the same number of zeros minus poles. I just don't see an example here. Thanks.
How about $f(z)=\frac{2}{z^2}$ and $g(z)=\frac{1/2-z}{z^3}$ with $D=\{z\in \mathbb{C} : |z|< 1 \}$