Yes. Calculate: *whats there*
seeing as it's in that interval, i suppose calculating the numeric value in t, which then multiplies the rest. the problem is that the upper limit is x...
Yes. Calculate: *whats there*
seeing as it's in that interval, i suppose calculating the numeric value in t, which then multiplies the rest. the problem is that the upper limit is x...
No, the problem is that $\displaystyle \int\frac{\cos(t)}{t}dt$ is not expressible in elementary terms.
Not along those lines then. Thanks! Any other suggestion how to approach it?
I don't any see possible way to do this. Maybe I am missing some little trick or something, but I have a feeling that this either isn't the whole problem or you wrote it wrong.
I don't any see possible way to do this. Maybe I am missing some little trick or something, but I have a feeling that this either isn't the whole problem or you wrote it wrong.
Maybe let $\displaystyle u=\int_1^x\frac{\cos t}{t}\,dt\implies \,du=\frac{\cos x}{x}\,dx$
So $\displaystyle \int\frac{\cos x}{x}\left(\int_1^x\frac{\cos t}{t}\,dt\right)^4\,dx\xrightarrow{u=\int_1^x\frac {\cos t}{t}\,dt}{}\int u^4\,du$