I'm having trouble knowing how to rearrange the inequality

The question is

Using epsilon, delta methods show that

lim f(x)= 2+x/x^2 = 3

{x->1}

I've gotten as far as saying | 2+x/x^2 - 3 | < epsilon

so is the delta part.. 0 < x-1 < delta ?????

I know all the steps but can't reach an inequality i'm happy with... I don't want to continue if i'm doing it wrong, time is of the essence!

Do I have to make the epsilon inequality similar to the delta one when i relate them? Or have I got it all wrong

Any help would be very much appreciated!

Thank you