I'm having trouble knowing how to rearrange the inequality
The question is
Using epsilon, delta methods show that
lim f(x)= 2+x/x^2 = 3
{x->1}
I've gotten as far as saying | 2+x/x^2 - 3 | < epsilon
so is the delta part.. 0 < x-1 < delta ?????
I know all the steps but can't reach an inequality i'm happy with... I don't want to continue if i'm doing it wrong, time is of the essence!
Do I have to make the epsilon inequality similar to the delta one when i relate them? Or have I got it all wrong
Any help would be very much appreciated!
Thank you