(and, of course, )
Using the definition of integration where g is a step function supported on [a,b], (f continuous on [a,b] )
show that for .
I would really appreciate any help with this. It's easy to show that if lambda is 0 you get the result but I am having trouble proving the rest. I just get tangled up in algebra, though I think I am trying to prove sup A = sup B, where A = where g is a step function supported on [a,b], and B = where g is a step function supported on [a,b], Thank you very much.