$\displaystyle h(t) = i (t+t^{2}), \ \ \ \ through \ \ \ t=0, \ \ \ Im(h(t))= constant $

and

$\displaystyle h(t) = i (t+t^{2}), \ \ \ \ through \ \ \ t=1, \ \ \ Im(h(t))= constant $

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- Nov 30th 2009, 11:11 AMpengchao1024sketch this path
$\displaystyle h(t) = i (t+t^{2}), \ \ \ \ through \ \ \ t=0, \ \ \ Im(h(t))= constant $

and

$\displaystyle h(t) = i (t+t^{2}), \ \ \ \ through \ \ \ t=1, \ \ \ Im(h(t))= constant $