

Good! You are probably finding it difficult to show that function is not continous at 0 because it is continuous at 0!
Given anyif x> 0, f(x)= x so we can just take
. That way, "if
,
". While if x< 0, f(x)= 0 so
for any x and so for
.
(The function is not differentiable at x= 0 but is continuous there.)