Good!You are probably finding it difficult to show that function is not continous at 0 because itiscontinuous at 0!

Given any if x> 0, f(x)= x so we can just take . That way, "if , ". While if x< 0, f(x)= 0 so for any x and so for .

(The function is notdifferentiableat x= 0 but is continuous there.)