how to prove x-(x^2)/x <= ln (1+x) <= x
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Fox $\displaystyle 0<x\le 1$ is... $\displaystyle \ln (1+x) = x -\frac{x^{2}}{2} + \frac{x^{3}}{3} - \frac{x^{4}}{4} + \dots $ (1) ... so that... Kind regards $\displaystyle \chi$ $\displaystyle \sigma$
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