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Math Help - proof

  1. #1
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    Post proof

    how to prove x-(x^2)/x <= ln (1+x) <= x
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  2. #2
    MHF Contributor chisigma's Avatar
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    Fox  0<x\le 1 is...

    \ln (1+x) = x -\frac{x^{2}}{2} + \frac{x^{3}}{3} - \frac{x^{4}}{4} + \dots (1)

    ... so that...

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    \chi \sigma
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