# lipschitz functions

• November 2nd 2009, 06:38 PM
dannyboycurtis
lipschitz functions
I need to show that $f(x)=\sqrt[3]{x}$ and
$g(x)=xsin(\frac{1}{x})$ for $x\in (0,1]$ are NOT Lipschitz.
Im a little lost on how to proceed.
• November 2nd 2009, 08:29 PM
dannyboycurtis
is it enough to show that they are not uniformly continuous?
if so Im still not sure how to show that f(x) is not uniformly continous
• November 3rd 2009, 04:36 AM
chisigma
Necessary condition for a function to be 'Lipschitz' is that its derivative is bounded in all the interval of definition...

Kind regards

$\chi$ $\sigma$