# sequence question !

• Oct 30th 2009, 06:02 PM
flower3
sequence question !
Let S be a nonempty bounded above subset of R . prove that there is a sequence $x_n \subseteq S$ of elements of S that converges to sup S
• Oct 30th 2009, 07:20 PM
proscientia
Quote:

Originally Posted by flower3
Let S be a nonempty bounded above subset of R . prove that there is a sequence $x_n \color{red}\in\color{black} S$ of elements of S that converges to sup S

Let $s=\sup S.$ Then $\forall\,n\in\mathbb N,$ $\exists\,x_n\in S$ such that $s\geqslant x_n>s-\frac1n$ since $s-\frac1n$ is not an upper bound for $S.$ The sequence $\left(x_n\right)_{n\,=\,1}^\infty$ converges to $s.$
• Oct 30th 2009, 11:40 PM
flower3
Quote:

Originally Posted by proscientia
Let $s=\sup S.$ Then $\forall\,n\in\mathbb N,$ $\exists\,x_n\in S$ such that $s\geqslant x_n>s-\frac1n$ since $s-\frac1n$ is not an upper bound for $S.$ The sequence $\left(x_n\right)_{n\,=\,1}^\infty$ converges to $s.$

it's not belongs to !!!!
both $x_n \ and \ S$ are sets ,so the truth subsets
• Oct 31st 2009, 01:30 AM
HallsofIvy
[PHP][/PHP] You said "a sequence of elements of S". Did you mean "a sequence of subsets of S"? sup S is definitely a number. How does a sequence of sets converge to a number? I think you have misunderstood the question.