Show that if K is compact and F is closed, then K intersect F is compact.
Alright this is what I have so far.
Suppose K is compact, which implies that K is closed and bounded. Since F is closed and K is closed, by theorem that means that K intersect F is closed as well. Since K intersect F is closed, that means that every cauchy sequence in K int. F has a limit that is an element of K int. F.
This is where I get stuck, I know that the definition of a compact set is:
A set K in R is compact if every sequence in K has a sub sequence that converges to a limit that is also in K.
I feel like that is what I concluded in my proof, so I could just say that means that K int. F is compact, however, it really isn't saying anything about sub sequences. Any help would be great!!!