d)if g(z)=z^2*e^z and y(t) is the path in part c, find an upper bound for

y(t)=i+3e^2it [0,pi/4]

i'm trying to figure out if i have done this right, Usually in other examples the
3e^2it is on its own, that is centred at zero, and i can use the fact that the magnitude will simply be the radius( three). With this example can i do that, or do i have to seperate the imagineray and real parts?

doing it like this seems quite involved:Anyway am i "overcomplicating it as i usually do! or is this the right approach.For the magnitude of the path i get:If anyone has done this type of problem i could use some help.




or should i use:


then g(z)=z^2*e^z
(then using the fact that the maximun of cos and sine is one.)
|∫g(z)dz|<=(e^3)30pi/4 =e^3(15pi)/2