# Math Help - limit of sin(n)/n, is this good?

1. ## limit of sin(n)/n, is this good?

to show the limit as n-> infinity of sin(n)/n= 0

absolute value( sin(n)/n - 0) = abs( sin(n)/n) < or equal to 1/n

< or equal to 1/n0 < epsilon
so we can choose n0 by the Archimedeian principle

is the way I handle the absolute value correct?

2. Originally Posted by mtlchris
to show the limit as n-> infinity of sin(n)/n= 0

absolute value( sin(n)/n - 0) = abs( sin(n)/n) < or equal to 1/n

< or equal to 1/n0 < epsilon
so we can choose n0 by the Archimedeian principle

is the way I handle the absolute value correct?

Looks fine to me...IF you can prove, or if you were given, that $\left|\frac{\sin n}{n}\right|<\frac{1}{n}$...

Tonio