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Math Help - limit of sin(n)/n, is this good?

  1. #1
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    limit of sin(n)/n, is this good?

    to show the limit as n-> infinity of sin(n)/n= 0

    absolute value( sin(n)/n - 0) = abs( sin(n)/n) < or equal to 1/n

    < or equal to 1/n0 < epsilon
    so we can choose n0 by the Archimedeian principle

    is the way I handle the absolute value correct?
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  2. #2
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    Quote Originally Posted by mtlchris View Post
    to show the limit as n-> infinity of sin(n)/n= 0

    absolute value( sin(n)/n - 0) = abs( sin(n)/n) < or equal to 1/n

    < or equal to 1/n0 < epsilon
    so we can choose n0 by the Archimedeian principle

    is the way I handle the absolute value correct?

    Looks fine to me...IF you can prove, or if you were given, that \left|\frac{\sin n}{n}\right|<\frac{1}{n}...

    Tonio
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