Prove. {a_n} converges, then it is Cauchy. I think I already got the answer. Can someone let me know if I'm allowed to start like this. |a_n - L|< e for n>N, and |a_m - L|< e for m>N |a_n - a_m| = |(a_n - L) - (a_m - L)|...
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Originally Posted by cgiulz Prove. {a_n} converges, then it is Cauchy. I think I already got the answer. Can someone let me know if I'm allowed to start like this. |a_n - L|< e for n>N, and |a_m - L|< e for m>N |a_n - a_m| = |(a_n - L) - (a_m - L)|... ... ... yes, it is indeed correct!
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