Prove. {a_n} converges, then it is Cauchy.

I think I already got the answer. Can someone let me know if I'm allowed to start like this.

|a_n - L|< e for n>N, and

|a_m - L|< e for m>N

|a_n - a_m| = |(a_n - L) - (a_m - L)|...

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- October 20th 2009, 05:49 PMcgiulz{a_n} converges => {a_n} is Cauchy; brief question
Prove. {a_n} converges, then it is Cauchy.

I think I already got the answer. Can someone let me know if I'm allowed to start like this.

|a_n - L|< e for n>N, and

|a_m - L|< e for m>N

|a_n - a_m| = |(a_n - L) - (a_m - L)|... - October 20th 2009, 05:52 PMDefunkt