So I have been asked to find the $\displaystyle \lim_{x\to 0} \frac{tan(x)}{x}=1$
Not sure how to do a delta/epsilon proof on this one
any help?
By definition is...
$\displaystyle \frac{\tan x}{x} = \frac{1}{\cos x}\cdot \frac{\sin x}{x}$ (1)
The second term of (1) is the product of a function that is 'well defined' in $\displaystyle x=0$ and a function the limit of which for $\displaystyle x \rightarrow 0$ is know as 'fundamental limit'...
Kind regards
$\displaystyle \chi$ $\displaystyle \sigma$