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Thread: One more proof with sequences

  1. #1
    Member thaopanda's Avatar
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    One more proof with sequences

    let {$\displaystyle a_n$} $\displaystyle n \in N$ be a sequence of real numbers and suppose that lim $\displaystyle a_n = A$ as n goes to infinity, where A > 0. Prove that there exists $\displaystyle N_o \in N $ such that $\displaystyle a_n > 0$ for all $\displaystyle n > N_o$
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  2. #2
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    Hi,

    if you write down definition of the limit of a sequence, then setting $\displaystyle \varepsilon = A/2$ (or $\displaystyle \varepsilon = A$ if you wish) gives you directly the answer.. try it
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