Thread: One more proof with sequences

1. One more proof with sequences

let { $a_n$} $n \in N$ be a sequence of real numbers and suppose that lim $a_n = A$ as n goes to infinity, where A > 0. Prove that there exists $N_o \in N$ such that $a_n > 0$ for all $n > N_o$

2. Hi,

if you write down definition of the limit of a sequence, then setting $\varepsilon = A/2$ (or $\varepsilon = A$ if you wish) gives you directly the answer.. try it