Letsuch that
and for all
and
such that
we have
. Is
harmonic in
?
I know the result is true if, but I don't know how to argue that if
then it's twice differentiable.
Okay, hadn't given this one much thought. Here's one proof for continous functions under slightly different assumptions; and although it is an improvement from thecase I'm still interested in the general case.
Letopen and
be such that for all
and
such that
we have
.
Letbe given by
where
is such that
. Define
. It is a standard result that if
then
where
.
With this in mind, letbe continous then:
![]()
This proves thatis harmonic in
. Now the issue here, if we wanted to generalize this procedure to
only integrable (or locally so), is that
has measure zero so our change into "polar coordinates" can not be applied as we did here.
Any comments or suggestions are appreciated.