Find V(x-x^2, [-1,2]) and V(cos(4PIx), [0,1]).
I don't even know what this notation means...
Any help??
That is not a standard notation, so what follows is only a guess. I suspect that the V stands for variation. So the question is possibly asking for the total variation of the function over the given interval.
For example, the function $\displaystyle x-x^2$ increases from –1 to 1/2, and then decreases from 1/2 to 2. So its total variation over the interval [–1,2] is the amount that it increases between x=–1 and x=1/2, plus the amount that it decreases between x=1/2 and x=2.