Show that if f is a measurable real-valued function and g is a continuous function defined on , then is measurable.

Please help! :'(

- September 30th 2009, 04:01 PMDark Sunthe composition of a measurable function with a continuous function is measurable
Show that if f is a measurable real-valued function and g is a continuous function defined on , then is measurable.

Please help! :'( - September 30th 2009, 07:18 PMDark Sun
This is what I have developed in a moment of clarity; Please tell me if I am right or wrong:

Certainly every continuous function is measurable, since every interval is measurable (P. 67). Therefore, is measurable.

Since is a real-valued function, restrict from to the co-domain of , which is a subset of . Since is measurable, the domain of restricted to the co-domain of has a measurable domain, that is, the set of all .

Also, the set of all elements not in the domain of are , which must neccessarily be measurable.

Therefore, since is measurable and , the domain of , and both and are measurable, then by Problem 21.a., the function restricted to the co-domain of must be measurable. Then is measurable since for all , an element in the co-domain of is defined, and restricted to these elements is measurable. - October 1st 2009, 08:07 PMputnam120
Look at the inverse of . So is measurable (U measurable) since, g is continuous and thus measurable. (pull backs of open sets by are open. and open sets generate the -algebra you are working with).