We have a, b ∈ R \ Q, a < b.
A = {x ∈ Q: a < x < b}
Show that A is clopen(open and close) in Q
i have being trying to solve this problem in the last 2hours
i need some hints or examples
thank you in advance
Assuming you give $\displaystyle \mathbb{Q}$ the topology inherited from $\displaystyle \mathbb{R}$ then open sets in $\displaystyle \mathbb{Q}$ are those of the form $\displaystyle A \cap \mathbb{Q}$ where $\displaystyle A$ is open in $\displaystyle \mathbb{R}$. Is $\displaystyle A_1=\{ x \in \mathbb{R} : a<x<b \}$ open? $\displaystyle A_1$ fails to be closed in $\displaystyle \mathbb{R}$ because it lacks $\displaystyle a$ and $\displaystyle b$, but is that a problem in $\displaystyle \mathbb{Q}$?