Suppose that a finite additive measure is continuous from below, I need to show that it is a measure.

Proof.

Let , all disjoint.

Define .

Note that: 1. and 2.

Then we have

Now, .

Is this correct? Thank you.

- September 27th 2009, 10:12 AMtttcomraderFinite additive measure is a measure if it is continuous from below
Suppose that a finite additive measure is continuous from below, I need to show that it is a measure.

Proof.

Let , all disjoint.

Define .

Note that: 1. and 2.

Then we have

Now, .

Is this correct? Thank you. - September 27th 2009, 10:28 AMMoo
Looks correct (Clapping)