Prove the following two dimensional form of the Bolzano-Weierstrass Theorem:
Ifis a sequence of points in they
plane, all of which lie in a rectangle,
then there is a subsequencewhich converges (i.e., the
and
each form a convergent sequence)
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Prove the following two dimensional form of the Bolzano-Weierstrass Theorem:
Ifis a sequence of points in they
plane, all of which lie in a rectangle,
then there is a subsequencewhich converges (i.e., the
and
each form a convergent sequence)
The bounded sequencehas a convergent subsequence
.
The bounded subsequencehas a convergent subsubsequence
.
The (sub)subsequencedoes the trick.
Thanks for your very helpful reply.
I'm a bit slow with this theoretical business, how do we knowis bounded and
is not?
Thank you very much.