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Math Help - Proving a limit

  1. #1
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    Proving a limit

    Can't figure this one out. :-(

    lim(n-->infinity) \frac{sin f(n)}{n^p}, p > 0, a constant, and f(n) represents images of any function f:N--->R.

    Any help with this?
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  2. #2
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    Quote Originally Posted by paupsers View Post
    lim(n-->infinity) \frac{sin f(n)}{n^p}, p > 0, a constant, and f(n) represents images of any function f:N--->R.
    \left| {\sin \left( {f(n)} \right)} \right| \leqslant 1
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