# Proving a limit

• Sep 22nd 2009, 10:03 AM
paupsers
Proving a limit
Can't figure this one out. :-(

lim(n-->infinity) $\frac{sin f(n)}{n^p}$, p > 0, a constant, and f(n) represents images of any function f:N--->R.

Any help with this?
• Sep 22nd 2009, 10:42 AM
Plato
Quote:

Originally Posted by paupsers
lim(n-->infinity) $\frac{sin f(n)}{n^p}$, p > 0, a constant, and f(n) represents images of any function f:N--->R.

$\left| {\sin \left( {f(n)} \right)} \right| \leqslant 1$