Define an injective map without using the axiom of choice.

I would define an injective function by , where if and if . But how would I define the map without using the axiom of choice?

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- Sep 13th 2009, 02:49 PMdori1123axiom of choice
Define an injective map without using the axiom of choice.

I would define an injective function by , where if and if . But how would I define the map without using the axiom of choice? - Sep 13th 2009, 03:01 PMThePerfectHacker