Observe your sum is bounded above by the integral of 1 \x^k from M to N-1, which you can easily evaluate directly obtaining two terms bounded by C/M^(k-1) as needed.

Results 1 to 2 of 2

- September 10th 2009, 07:53 AM #1

- Joined
- Dec 2008
- Posts
- 62

- September 11th 2009, 06:52 AM #2

- Joined
- Sep 2009
- Posts
- 2