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About LinkBacksHi everyone,
I am having trouble calculating the following limit
I know thatis equal to
, but what do I do with
?
I would appreciate any help.
Thank you very much guys for your responses!
Using l'Hospital's rule would of course be possible, but it does render the numerator of the fraction a bit ugly, thus I don't think that using l'Hospital's rule was the original intention.
I did the expansion byand simplified the numerator, but I have to admit that I got stuck again at this point:
(\sqrt{1+\sin^2{x}}+\sqrt{1-\sin^2{x}})}})
Originally Posted by thomasdotnet
Thank you very much guys for your responses!
Using l'Hospital's rule would of course be possible, but it does render the numerator of the fraction a bit ugly, thus I don't think that using l'Hospital's rule was the original intention.
I did the expansion by
(\sqrt{1+\sin^2{x}}+\sqrt{1-\sin^2{x}})}}=)
}{(1-\cos{x})(\sqrt{1+\sin^2{x}}+\sqrt{1-\sin^2{x}})}})
![={\frac{2[(1-\cos{x})(1+\cos{x})]}{(1-\cos{x})(\sqrt{1+\sin^2{x}}+\sqrt{1-\sin^2{x}})}}](http://latex.codecogs.com/png.latex?={\frac{2[(1-\cos{x})(1+\cos{x})]}{(1-\cos{x})(\sqrt{1+\sin^2{x}}+\sqrt{1-\sin^2{x}})}})
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