find the general solution:
y" + 4y = 3sin(2x)
I'm able to solve for the homogeneous by:
y" + 4y = 0
y(x) = Asin(2x) + Bcos(2x)
however I'm unsure about the particular solution for 3sin(2x).
any hints to point me in the right direction would be much appreciated. Thank you