find the general solution:

y" + 4y = 3sin(2x)

I'm able to solve for the homogeneous by:

y" + 4y = 0

y(x) = Asin(2x) + Bcos(2x)

however I'm unsure about the particular solution for 3sin(2x).

any hints to point me in the right direction would be much appreciated. Thank you