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Thread: Laplace Transforms of DE II

  1. August 25th 2009, 11:26 PM #1
    khanim
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    Laplace Transforms of DE II

    Another Problem

    D^{2}y + 2Dy -3y = e^{-3t}

    All initial condtions are 0. I am having a problem with the partial fraction part

    This is how far I got

    Y(s)= \frac{1}{((s+1)^{2}-4)(s+3)}

    I dont think I am decomposing it properly hence I ma not getting the correct answer
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  2. August 25th 2009, 11:59 PM #2
    chisigma
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    Your work is correct... what is difficult to undestand however is why the term s^{2} + 2s -3 = (s+3) (s-1) is written as (s+1)^{2} -4...

    ... anyway you can proceed 'step by step' exactly as in your previous post...

    Kind regards

    \chi \sigma
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  3. August 27th 2009, 12:25 AM #3
    khanim
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    Thx Chi Sigma

    The lecturer started the solution that way, so I didn't bother checking :-(
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