so solve the system
A+B=1
4A+6B=3
The solution of a certain differential equation is of the form
y(t)=aexp(4t)+bexp(6t), where a and b are constants.
The solution has initial conditions y(0)=1 and y'(0)=3.
Find the solution by using the initial conditions to get linear equations for a and b.
can anyone help me with this one.