whats the laplase transformation of this one..

**transgalactic** · August 17th 2009, 01:31 PM

$<br /> \frac{-2e^{-s}}{s^3}<br />$

i know that e ill make u function
but i dont know the rest

**Chris L T521** · August 17th 2009, 01:53 PM

Originally Posted by transgalactic

$<br /> \frac{-2e^{-s}}{s^3}<br />$

i know that e ill make u function
but i dont know the rest

Recall that $\mathcal{L}^{-1}\left\{e^{-as}F\left(s\right)\right\}=u\left(t-a\right)f\left(t-a\right)$

So here, we see that $-2e^{-s}{s^3}=-e^{-s}\frac{2!}{s^3}$

Therefore, $\mathcal{L}^{-1}\left\{-e^{-s}\frac{2!}{s^3}\right\}=-u\left(t-1\right)\cdot\left(t-1\right)^2$

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