1. ## Challenging problem

I've been trying to solve and find the solution of this problem by
method of exact equations but eventually I got stuck.

[y^(x) Cos(2x) -2e^(xy) Sin(2x) + 2x]dx + [xe^(xy) Cos(2x) -3]dy = 0

2. Originally Posted by lorenzo
I've been trying to solve and find the solution of this problem by
method of exact equations but eventually I got stuck.

[y^(x) Cos(2x) -2e^(xy) Sin(2x) + 2x]dx + [xe^(xy) Cos(2x) -3]dy = 0
May I ask, is the a chance that the term above in red is

$y\,e^{xy} \cos 2x$?

3. Originally Posted by Danny
May I ask, is the a chance that the term above in red is

$y\,e^{xy} \cos 2x$?
I checked my notes again to confirm. But, it is:
$ye^{x} \cos 2x$

4. Originally Posted by lorenzo
I checked my notes again to confirm. But, it is:
$ye^{x} \cos 2x$
You'll notice that you've changed the term from your first post. When you say notes, are you refering to classroom notes that you took?

5. Sorry my mistake.

is y^(x) Cos 2x

Yes the notebook I used to work on.