I need help on this problem.. i think its suppose to be simple but i don't know how to get the answer.

the problem is:

solve the initial-value problem 2t^2y''+3ty'-y=0; y(1)=2,y'(1)=1

the answer is y(t)=2(t^1/2)

thank you

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- July 5th 2009, 12:08 AM #1

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