1. ## I need help

I need help on this problem.. i think its suppose to be simple but i don't know how to get the answer.

the problem is:
solve the initial-value problem 2t^2y''+3ty'-y=0; y(1)=2,y'(1)=1

thank you

2. Originally Posted by blazingwes
I need help on this problem.. i think its suppose to be simple but i don't know how to get the answer.

the problem is:
solve the initial-value problem 2t^2y''+3ty'-y=0; y(1)=2,y'(1)=1

thank you
in your lecture notes look for "Euler differential equation." if you have no lecture notes, then Google it.

3. See here.

4. Originally Posted by Chris L T521
See here.
Off topic, but Chris, your avatar is hilarious!

5. hmm if i did it that way.. why was i given y(1)=2,y'(1)=1????

6. Originally Posted by blazingwes
hmm if i did it that way.. why was i given y(1)=2,y'(1)=1????
What you usually find first when you solve a differential equation is the general solution (with arbitrary constants). The initial conditions are given so you can find the constants $c_1$ and $c_2$ from the general solution.