Thread: I need help

I need help on this problem.. i think its suppose to be simple but i don't know how to get the answer.

the problem is:
solve the initial-value problem 2t^2y''+3ty'-y=0; y(1)=2,y'(1)=1

the answer is y(t)=2(t^1/2)

thank you

Originally Posted by blazingwes

I need help on this problem.. i think its suppose to be simple but i don't know how to get the answer.

the problem is:
solve the initial-value problem 2t^2y''+3ty'-y=0; y(1)=2,y'(1)=1

the answer is y(t)=2(t^1/2)

thank you

in your lecture notes look for "Euler differential equation." if you have no lecture notes, then Google it.

See here.

Originally Posted by Chris L T521

See here.

Off topic, but Chris, your avatar is hilarious!

hmm if i did it that way.. why was i given y(1)=2,y'(1)=1????

Originally Posted by blazingwes

hmm if i did it that way.. why was i given y(1)=2,y'(1)=1????

What you usually find first when you solve a differential equation is the general solution (with arbitrary constants). The initial conditions are given so you can find the constants and from the general solution.