I suppose this is probably pretty easy for people in the know
Recently I've been using Wolfram Alpha, which is an amazing tool, I mainly like it for showing the steps in calculus, however it doesn't want to give the steps for differential equations
Anyway, the question is as follows...
Now I know it's separable so I've put the square root bit under the y'
then I integrated both sides separately
leaving me with
However wolfram alpha is giving a rather more complicated answer of
So is WA wrong, or if it isn't, what steps have been taken to get to that answer?
Thanks for clarifying my work, but check for yourself
I'm almost certian i've entered it corectly, and i'm confident WA is reading the input correctly.
Your answer and the one by WA are both correct and are simply two different expressions for the same thing but yours is the simpler and hence better one!
Using the identity
we have that
since and where
where is the constant, , in your expression.
Welcome to the world of automated computer algebra!