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Math Help - Find the solution

  1. #1
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    Find the solution

    find the solution of the ivp

    y' = (1-y^2)x^2
    y(0) = 0
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  2. #2
    Behold, the power of SARDINES!
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    Quote Originally Posted by matty888 View Post
    find the solution of the ivp

    y' = (1-y^2)x^2
    y(0) = 0
    The equation is seperatable

    \frac{dy}{dx}=(1-y^2)x^2 \iff \frac{dy}{1-y^2}=x^2dx

    All you need to do from here is integrate.

    Note that

    \frac{1}{1-y^2}=\frac{\frac{1}{2}(1-y)+\frac{1}{2}(1+y)}{(1-y)(1+y)}+\frac{\frac{1}{2}}{1+y}+\frac{\frac{1}{2}  }{1-y}
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  3. #3
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    More help needed

    thanks empty set
    i kinda have this bit
    could you tell me if the answer

    +- sqrt(1-e^(2/3.x^3))

    sound any good????
    thanks
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