find the solution of the ivp y' = (1-y^2)x^2 y(0) = 0
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Originally Posted by matty888 find the solution of the ivp y' = (1-y^2)x^2 y(0) = 0 The equation is seperatable All you need to do from here is integrate. Note that
thanks empty set i kinda have this bit could you tell me if the answer +- sqrt(1-e^(2/3.x^3)) sound any good???? thanks
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