Im struggling with finding the 1st and 2nd derivatives of these functions f(x)= tan^-1 3x So far i have done: dy/dx = 3 (1/1+(3x)^2) = 3/ (1+9x^2) Im not sure where to go from there Any help much appraciated.
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Originally Posted by jamm89 Im struggling with finding the 1st and 2nd derivatives of these functions f(x)= tan^-1 3x So far i have done: dy/dx = 3 (1/1+(3x)^2) = 3/ (1+9x^2) Im not sure where to go from there Any help much appraciated. Use the chain rule on to find
so i use chain rule on this? u= y= du/dx = 54x dy/du= Can someone finish this off for me please as i have no idea where to go from here thanks
Originally Posted by jamm89 so i use chain rule on this? u= y= du/dx = 54x dy/du= Can someone finish this off for me please as i have no idea where to go from here thanks
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