can anyone help me out wif this problem??
maybe...its an easy cake for u..
dy/dx=xe^(y-x^2) and y(0)=0
I have to solve the initial value....
and show all intermediate steps in my solution of the differential equation.
thanks
can anyone help me out wif this problem??
maybe...its an easy cake for u..
dy/dx=xe^(y-x^2) and y(0)=0
I have to solve the initial value....
and show all intermediate steps in my solution of the differential equation.
thanks
First the question belongs in the ODE forum not the chat room and it is seperable
Remember that
$\displaystyle e^{y-x^2}=e^{y}\cdot e^{-x^2}$
$\displaystyle \frac{dy}{dx}=xe^{y}e^{-x^2}\iff \frac{dy}{e^{y}}=xe^{-x^2}dx \iff e^{-y}dy=xe^{-x^2}dx$
Just integrate the use your IC.